Last time we introduced the fact that spinning flywheels are subject to both linear and angular velocities, along with a formula that allows us to calculate these quantities for a single part of the flywheel, designated Here again is the basic
where, Here again is the formula used to calculate linear and angular velocities for a single part v, angular velocity by _{A}ω, and where r is the distance of part _{A}A from the flywheel’s center of rotation.
Working with these two formulas, we’ll insert equation (2) into equation (1) to obtain a
× m _{A}× (r)_{A} × ω (3)^{2}which simplifies to,
× m _{A}× r_{A}^{2} × ω (4)^{2} Equation (4) is a great place to begin to calculate the amount of m, and is a unique distance, r, from the flywheel’s center of rotation, and all these parts must be accounted for in order to arrive at a calculation for the total amount of .kinetic energy contained within a spinning flywheel
Put another way, we must add together all the known as the moment of inertia.kinetic energy of a flywheel For now, let’s just consider the flywheel’s parts in general terms. A general formula to compute the is,spinning flywheel
× ω (5)^{2} We’ll discuss the significance of each of these variables next time when we arrive at a method to calculate the spinning flywheel. Copyright 2017 – Philip J. O’Keefe, PE Engineering Expert Witness Blog ____________________________________ |

Tags: angular velocity, center of rotation, engineering, flywheel, kinetic energy, linear velocity, mass, moment of inertia