Sometimes things which appear simple turn out to be rather complex. Such is the case with the Euler-Eytelwein Formula, a small formula with a big job. It computes how friction, an omnipresent phenomenon in mechanical assemblies, contributes to the transmission of mechanical power. Today we’ll .angle of wrap
Here again is the basis for our calculations, the Euler-Eytelwein Formula.
e^{(μ} (1)^{θ)} To recap what we’ve discussed thus far, T is the loose side tension. It’s just going along for the ride. The term _{2}e is Euler’s Number, a constant equal to 2.718, and the coefficient of friction, μ, for contact points between the belt and pulleys is 0.3 based on their materials. The θ, is,
where,
D) _{1} – D_{2}÷ 2x) (3) By direct measurement we’ve determined the pulleys’ diameters, D, are equal to 1 foot and 0.25 feet respectively. The term _{2}x is the distance between the two pulley shafts, 3 feet. The term sinis a trigonometric function known as ^{-1 }inverse sine, a button commonly found on scientific calculators.Inserting our known values into equation (3) we arrive at,
foot – 0.25 feet) ÷ 2 × (3 feet)) (4)
We can now incorporate equation (5) into equation (2) to solve for
Inserting the values for
× 2.718^{(}^{0.3 ×}^{ 2.89)} (8)
We have at this point solved for over half of the unknown variables in the Euler-Eytelwein Formula. We still can’t solve for T. But that will change next time when we introduce yet another _{2} this one to determine the amount of mechanical power present in our pulley-belt system.formula,
Copyright 2017 – Philip J. O’Keefe, PE Engineering Expert Witness Blog ____________________________________ |

Tags: angle of wrap, belt, coefficient of friction, Euler-Eytelwein Formula, Euler's Number, friction, loose side tension, mechanical assemblies, mechanical power, pulley, pullies, tight side tension