It’s been awhile since we began our discussion of a pulley-belt assembly operating within a hydroponics plant, and we’ve solved for a lot variables and derived many equations along the way. Today we’ll tackle the two remaining variables, T , its loose side tension, and we’ll determine exactly what _{2} will belt width power transmission within our system.optimize
Last time we converted mechanical power, 2,200 feet/second (1) This equation will allow us to solve for T, and from there we’ll develop a value for the _{2}optimum belt width.Previously, we determined from the Euler-Eytelwein Formula that,
T (2)_{2}Substituting equation (2) into equation (1), we get, 2,200 feet/second (3)Reducing this equation with algebra we arrive at,
pounds (4) We can now insert equation (4) into equation (2) and calculate
pounds (5)
pounds (6)
specified by the manufacturer to be 300 pounds per inch of belt,, which makes the minimum width to be used to width belt power transmission within our pulley-belt assembly,optimize
300 pounds per inch (7)
We can use a of 3.22 inches to safely transmit 4 horsepower from the engine to the pump without incurring breakage and slippage along the belt, thereby width power transmission within our assembly. If we used a narrower belt, breaking and slippage would occur. If we used a wider optimizing an unnecessary expense would be incurred.belt,Next time we’ll begin a discussion on flywheels as they apply to rotating machinery like gasoline and steam engines.
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